10x^2=0.25

Solution for 10x^2=0.25 equation:

10x^2=0.25

We move all terms to the left:

10x^2-(0.25)=0

We add all the numbers together, and all the variables

10x^2-0.25=0

a = 10; b = 0; c = -0.25;
Δ = b2-4ac
Δ = 02-4·10·(-0.25)
Δ = 10
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{10}}{2*10}=\frac{0-\sqrt{10}}{20}
=-\frac{\sqrt{}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{10}}{2*10}=\frac{0+\sqrt{10}}{20}
=\frac{\sqrt{}}{20}
$